{"id":"01a14e04-a977-79ef-a88b-3f5d20d7cfe5","rev":4439,"sorte":"oeuvre","format":"cadrame-fiche-1","anciens":[],"versions":[],"categorie":"general","affirmations":{"tag":[{"id":"01a14e08-2b76-7f3b-8d54-2229fd103e0f","rev":4439,"rang":"normal","valeur":{"entite":"01a14c74-a1ac-7f21-936f-b15dde8eb1a2"}}],"kind":[{"id":"01a14e08-2b76-77e2-89e1-11f490afe078","rev":4439,"rang":"normal","valeur":{"entite":"01a148fa-29cb-71f7-a260-02f0d21146f3"}}],"title":[{"id":"01a14e04-a977-7e9c-b501-173abcaae358","rev":3715,"rang":"prefere","valeur":{"texte":"The Lois Quagmire","langue":"en"}},{"id":"01a14e04-a978-71d6-ba0f-f02f579122c4","rev":3715,"rang":"prefere","valeur":{"texte":"Lois Quagmire","langue":"de"}}],"director":[{"id":"01a14e08-2b77-76ed-844a-05c39583a414","rev":4439,"rang":"normal","valeur":{"entite":"01a14e05-e0e5-76e8-87e1-018698c0b24b"}}],"description":[{"id":"01a14e04-a978-7502-97a9-a85eb71208af","rev":3715,"rang":"normal","valeur":{"texte":"episode of Family Guy (S20 E12)","langue":"en"}},{"id":"01a14e04-a978-781f-9679-f33eaa2780d2","rev":3715,"rang":"normal","valeur":{"texte":"Folge von Family Guy","langue":"de"}},{"id":"01a14e04-a978-7b16-8285-7923d918634c","rev":3715,"rang":"normal","valeur":{"texte":"حلقة من سلسلة فاميلي غاي","langue":"ar"}},{"id":"01a14e04-a978-7e41-a718-f423f7b2b4d8","rev":3715,"rang":"normal","valeur":{"texte":"episodio de Padre de familia (T20 E12)","langue":"es"}},{"id":"01a14e04-a979-715e-b1c2-56af8898d1ba","rev":3715,"rang":"normal","valeur":{"texte":"dodicesimo episodio della ventesima stagione de I Griffin","langue":"it"}},{"id":"01a14e04-a979-745f-91c6-f6ba59dd5352","rev":3715,"rang":"normal","valeur":{"texte":"épisode des Griffin","langue":"fr"}}],"publication":[{"id":"01a14e04-a979-7da2-8eac-9118cc1c4a5a","rev":3715,"rang":"normal","valeur":{"date":"2022-02-27","precision":"jour"}}],"wikidata_id":[{"id":"01a14e04-a977-7b73-8edc-7b2a610e9278","rev":3715,"rang":"normal","valeur":{"chaine":"Q110889383"}}],"imdb_title_id":[{"id":"01a14e04-a97a-709d-8d0e-bff166959335","rev":3715,"rang":"normal","valeur":{"chaine":"tt17058480"}}],"original_title":[{"id":"01a14e04-a979-7a7d-ac3c-28369b0f29dc","rev":3715,"rang":"normal","valeur":{"texte":"The Lois Quagmire","langue":"en"}}],"part_of_series":[{"id":"01a14e08-2b76-7b73-b4c0-13c52df07f67","rev":4439,"rang":"normal","valeur":{"entite":"01a14c71-bdde-72a4-af98-3a04dc4011da"},"qualificatifs":{"number":{"chaine":"12"},"season":{"quantite":20}}}],"tmdb_episode_id":[{"id":"01a14e04-a97a-764a-ba0a-f4c6f84999b8","rev":3715,"rang":"normal","valeur":{"chaine":"3294628"}}],"tvdb_episode_id":[{"id":"01a14e04-a97a-7380-8208-ea0d85b53fbd","rev":3715,"rang":"normal","valeur":{"chaine":"8751576"}}],"wikipedia_article":[{"id":"01a14e04-a979-777f-a608-ce6bb9997696","rev":3715,"rang":"normal","valeur":{"texte":"The Lois Quagmire","langue":"en"}}],"original_broadcaster":[{"id":"01a14e08-2b77-7364-8ce4-d0e92fe2eb7b","rev":4439,"rang":"normal","valeur":{"entite":"01a14c72-a20e-742d-bfa9-06baed175e09"}}]},"affichage":{"titre":"The Lois Quagmire","langue":"en"}}