{"id":"01a14e04-719f-7344-812f-6067f17ee918","rev":4429,"sorte":"oeuvre","format":"cadrame-fiche-1","anciens":[],"versions":[],"categorie":"general","affirmations":{"kind":[{"id":"01a14e08-1122-7e55-9e68-f0cbf8e20f63","rev":4429,"rang":"normal","valeur":{"entite":"01a148fa-29cb-71f7-a260-02f0d21146f3"}}],"title":[{"id":"01a14e04-719f-7740-97f0-4c651ff3a5d2","rev":3659,"rang":"prefere","valeur":{"texte":"Murder? ... Anyone? ... Anyone? ... Bueller?","langue":"en"}},{"id":"01a14e04-719f-79e4-980a-670f3d0a1656","rev":3659,"rang":"prefere","valeur":{"texte":"La rimpatriata","langue":"it"}},{"id":"01a14e04-719f-7cbf-9d88-a61ff0d6c218","rev":3659,"rang":"prefere","valeur":{"texte":"Ein Shawn für alle Fälle","langue":"de"}}],"description":[{"id":"01a14e04-719f-7f92-9300-022925fbfa21","rev":3659,"rang":"normal","valeur":{"texte":"episode of Psych (S3 E2)","langue":"en"}},{"id":"01a14e04-71a0-7250-aff1-6bdd69be06c1","rev":3659,"rang":"normal","valeur":{"texte":"Folge von Psych","langue":"de"}},{"id":"01a14e04-71a0-74f2-96af-a00555d4e7e5","rev":3659,"rang":"normal","valeur":{"texte":"aflevering van Psych","langue":"nl"}},{"id":"01a14e04-71a0-778e-a489-9869a05f67b1","rev":3659,"rang":"normal","valeur":{"texte":"clár sa tsraith theilifíse Psych (S3 E2)","langue":"ga"}},{"id":"01a14e04-71a0-7a3c-8700-6f83671da410","rev":3659,"rang":"normal","valeur":{"texte":"حلقة من سلسلة سايك","langue":"ar"}},{"id":"01a14e04-71a0-7d1b-9048-f8f8759f27d4","rev":3659,"rang":"normal","valeur":{"texte":"secondo episodio della terza stagione di Psych","langue":"it"}},{"id":"01a14e04-71a0-7ffa-b6b3-2ea8a195abba","rev":3659,"rang":"normal","valeur":{"texte":"épisode de Psych : Enquêteur malgré lui","langue":"fr"}}],"publication":[{"id":"01a14e04-71a1-77f2-a6d3-ee65c50c869f","rev":3659,"rang":"normal","valeur":{"date":"2008-07-25","precision":"jour"}}],"wikidata_id":[{"id":"01a14e04-719f-749d-b4da-49738272e8b6","rev":3659,"rang":"normal","valeur":{"chaine":"Q50814456"}}],"imdb_title_id":[{"id":"01a14e04-71a1-7299-bfff-60dba545171a","rev":3659,"rang":"normal","valeur":{"chaine":"tt1189424"}}],"original_title":[{"id":"01a14e04-71a1-7541-a761-ac7f1797b885","rev":3659,"rang":"normal","valeur":{"texte":"Murder? ... Anyone? ... Anyone? ... Bueller?","langue":"en"}}],"part_of_series":[{"id":"01a14e08-1123-71a0-90ec-6c70435f031a","rev":4429,"rang":"normal","valeur":{"entite":"01a14c71-dc55-7647-8834-cadf2c6698e2"},"qualificatifs":{"number":{"chaine":"2"},"season":{"quantite":3}}}],"tmdb_episode_id":[{"id":"01a14e04-71a1-7d39-a9ed-0c24744d8eac","rev":3659,"rang":"normal","valeur":{"chaine":"66805"}}],"tvdb_episode_id":[{"id":"01a14e04-71a1-7a88-b25c-1702184185ea","rev":3659,"rang":"normal","valeur":{"chaine":"374839"}}]},"affichage":{"titre":"Murder? ... Anyone? ... Anyone? ... Bueller?","langue":"en"}}