{"id":"01a14e04-70fa-75df-aa28-e6f2c7ef24f3","rev":4429,"sorte":"oeuvre","format":"cadrame-fiche-1","anciens":[],"versions":[],"categorie":"general","affirmations":{"kind":[{"id":"01a14e08-1112-7057-8ef8-0a212363b2a2","rev":4429,"rang":"normal","valeur":{"entite":"01a148fa-29cb-71f7-a260-02f0d21146f3"}}],"title":[{"id":"01a14e04-70fa-79e5-beb4-1e465392a97c","rev":3658,"rang":"prefere","valeur":{"texte":"Spellingg Bee","langue":"en"}},{"id":"01a14e04-70fa-7cf8-b151-cad47f57af0b","rev":3658,"rang":"prefere","valeur":{"texte":"Maestro di parole","langue":"it"}},{"id":"01a14e04-70fc-77f2-b030-e790a396cf02","rev":3658,"rang":"prefere","valeur":{"texte":"So spannend kann ein Buchstabierwettbewerb sein!","langue":"de"}}],"director":[{"id":"01a14e08-1112-73d7-a960-5b455b574863","rev":4429,"rang":"normal","valeur":{"entite":"01a14e06-24a7-7f6b-9f5d-fd8393ac3109"}}],"description":[{"id":"01a14e04-70fd-74ff-894c-fd9f266b21f4","rev":3658,"rang":"normal","valeur":{"texte":"aflevering van Psych","langue":"nl"}},{"id":"01a14e04-70fd-7a2f-94cb-c8bb88f22ae7","rev":3658,"rang":"normal","valeur":{"texte":"Folge von Psych","langue":"de"}},{"id":"01a14e04-70fd-7e27-9834-82a0bf93abc2","rev":3658,"rang":"normal","valeur":{"texte":"épisode de Psych : Enquêteur malgré lui","langue":"fr"}},{"id":"01a14e04-70fe-7486-be9f-f16ca068f7dc","rev":3658,"rang":"normal","valeur":{"texte":"episode of Psych (S1 E2)","langue":"en"}},{"id":"01a14e04-7100-7d04-b227-b9a0b3d497fb","rev":3658,"rang":"normal","valeur":{"texte":"clár sa tsraith theilifíse Psych (S1 E2)","langue":"ga"}},{"id":"01a14e04-7101-7ed4-aafd-9f5090cbdb3d","rev":3658,"rang":"normal","valeur":{"texte":"حلقة من سلسلة سايك","langue":"ar"}},{"id":"01a14e04-7102-7489-b0f6-b96d6bd09cd1","rev":3658,"rang":"normal","valeur":{"texte":"secondo episodio della prima stagione di Psych","langue":"it"}}],"publication":[{"id":"01a14e04-7102-7e93-9a8e-3355e3c54f2f","rev":3658,"rang":"normal","valeur":{"date":"2006-07-14","precision":"jour"}}],"wikidata_id":[{"id":"01a14e04-70fa-7721-9370-91f55f7828a5","rev":3658,"rang":"normal","valeur":{"chaine":"Q16744181"}}],"screenwriter":[{"id":"01a14e08-1112-7e8b-b1c9-8cf0ce74257a","rev":4429,"rang":"normal","valeur":{"entite":"01a14c74-4b27-71a4-922b-0384f2f1be13"}}],"imdb_title_id":[{"id":"01a14e04-7102-7b41-9e86-bc78e908979c","rev":3658,"rang":"normal","valeur":{"chaine":"tt0828981"}}],"original_title":[{"id":"01a14e04-7103-71a9-839c-cecb6a20bcf1","rev":3658,"rang":"normal","valeur":{"texte":"Spellingg Bee","langue":"en"}}],"part_of_series":[{"id":"01a14e08-1112-7969-ba9d-d6d5c9f3c670","rev":4429,"rang":"normal","valeur":{"entite":"01a14c71-dc55-7647-8834-cadf2c6698e2"},"qualificatifs":{"number":{"chaine":"2"},"season":{"quantite":1}}}],"tmdb_episode_id":[{"id":"01a14e04-7103-776c-9472-00190fd3f323","rev":3658,"rang":"normal","valeur":{"chaine":"66774"}}],"tvdb_episode_id":[{"id":"01a14e04-7103-7491-9b3a-9526b50edbdf","rev":3658,"rang":"normal","valeur":{"chaine":"307498"}}],"wikipedia_article":[{"id":"01a14e04-7102-77ff-b820-74f6250e748e","rev":3658,"rang":"normal","valeur":{"texte":"Spellingg Bee","langue":"en"}}]},"affichage":{"titre":"Spellingg Bee","langue":"en"}}